6[1-(4y-3)]=8(4-2y)

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Solution for 6[1-(4y-3)]=8(4-2y) equation:


Simplifying
6[1 + -1(4y + -3)] = 8(4 + -2y)

Reorder the terms:
6[1 + -1(-3 + 4y)] = 8(4 + -2y)
6[1 + (-3 * -1 + 4y * -1)] = 8(4 + -2y)
6[1 + (3 + -4y)] = 8(4 + -2y)

Combine like terms: 1 + 3 = 4
6[4 + -4y] = 8(4 + -2y)
[4 * 6 + -4y * 6] = 8(4 + -2y)
[24 + -24y] = 8(4 + -2y)
24 + -24y = (4 * 8 + -2y * 8)
24 + -24y = (32 + -16y)

Solving
24 + -24y = 32 + -16y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '16y' to each side of the equation.
24 + -24y + 16y = 32 + -16y + 16y

Combine like terms: -24y + 16y = -8y
24 + -8y = 32 + -16y + 16y

Combine like terms: -16y + 16y = 0
24 + -8y = 32 + 0
24 + -8y = 32

Add '-24' to each side of the equation.
24 + -24 + -8y = 32 + -24

Combine like terms: 24 + -24 = 0
0 + -8y = 32 + -24
-8y = 32 + -24

Combine like terms: 32 + -24 = 8
-8y = 8

Divide each side by '-8'.
y = -1

Simplifying
y = -1

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